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Home » n = 20 \quad \text(since \( n \) must be positive) - wispro

n = 20 \quad \text(since \( n \) must be positive) - wispro

📅 March 11, 2026 👤 scraface

Mar 11, 2026

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But x must be integer — recheck:
2(5x - 4) = 7x + 2 → 10x - 8 = 7x + 2 → 3x = 10 → x = 10/3 — invalid.
Wait — try solving again:
2(5x - 4) = 7x + 2 → 10x - 8 = 7x + 2 → 3x = 10 → x = 10/3 → not integ...
Wait — perhaps misstep. Try specific values.
No integer solution? But problem implies one.
Wait — try solving correctly:
10x - 8 = 7x + 2 → 3x = 10 → x = 10/3 — not whole.
But ratio 5:7 → try x=2 → boys=10, girls=14 → after: boys=6, girls=16...
x=1 → 5,7 → 3:12 = 1:4.

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